Question

Find the sum of all multiples of 6 from 1 to 200 ​

Answer 1

Answer:

a = 6 , d = 6

a1 = 6 and al = 198

198 = 6 + ( n- 1 ) 6

192 = 6n - 6

6n = 198

n = 33

$sum = \frac{n}{2} (a + al) \\ = \frac{33}{2} (6 + 198) \\ = \frac{33 \times 204}{2} \\ = \frac{33 \times 102}{1} \\ = 3366$

Hope it helps

Answer 2

Answer:

3366

Step-by-step explanation: