Math, asked by ankitkumawat4601, 7 months ago

find the sum of all multiples of 7 lying between 1 and 100​

Answers

Answered by SHIVAMBANDE18122005
1

Step-by-step explanation:

Step-by-step explanation:the first no after 100 divisible by 7 is 105 and last before 1000 is 994. n= ? From 994, n can be obtained. Thus, the answer is 70336.

Answered by KailashHarjo
2

Given,

Multiplies of seven lying between 1-100

To find,

The sum of multiplies of seven lying between 1-100 =?

Solution,

Multiples of seven lying between 1-100 are given as,

7,14,...,98

We know,

a_n=a+(n-1)d

98=7+(n-1)7\\

n=14

Now finding the sum of fourteen terms.

We know,

S_n=\frac{n}{2}[2a+(n-1)d]

Now on putting the values we get,

S_n=\frac{14}{2}[2\times7+(14-1)\times 7]\\

S_n=7[14+13\times7]\\

S_n=735

So the sum of all multiples of seven lying between one and hundred is 735.

Hence, the sem of all multiples of 7 lying between 1 and 100 is 735.

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