Find the sum of all multiples of 7 lying between 103 and 999.
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multiples of 7 lying between 103 and 999
are 105,112,119.............994
AP= 105,112,119.............994
a=105,d=112-105=7
nth term=994
nth term= a+(n-1)d
994= 105+(n-1)7
994-105=(n-1)7
889=(n-1)7
n-1= 889/7
n-1=127
n=128
n=128
sum of all 128 terms
=n/2(a+nth term)
=128/2(105+994)
=128/2(1099)
=64*1099
=70336
Sum of all the multiples of 7 between 103 and 994 is 70336
PLEASE MARK IT AS BRAINLIEST
are 105,112,119.............994
AP= 105,112,119.............994
a=105,d=112-105=7
nth term=994
nth term= a+(n-1)d
994= 105+(n-1)7
994-105=(n-1)7
889=(n-1)7
n-1= 889/7
n-1=127
n=128
n=128
sum of all 128 terms
=n/2(a+nth term)
=128/2(105+994)
=128/2(1099)
=64*1099
=70336
Sum of all the multiples of 7 between 103 and 994 is 70336
PLEASE MARK IT AS BRAINLIEST
sahil117196:
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