Question

Find the sum of all multiples of 8 between 4 and 130

Answer 1

-120 is the answer of your question

Answer 2

Answer:

1088

Step-by-step explanation:

WE WILL BE USING THE A.P. SUM FORMULA

SO ATQ= A= 8 N=? , D = 8 An= 128 (128 is the last multiple of 8 before 130)

TO FIND N

An = 128 = A + (n-1)d

128= 8 + (n-1)8

128-8 = (n-1)8

120/8 = n-1

n= 15+1

n= 16

TO FIND SUM

S16 = n/2{2a +(n-1)d}

= 16/2 {2×8 + (16-1)8}

=8(16+120)

=8(136)

=1088