Question

find the sum of all multiples of 8 lying between 201 and 950.

Answer 1

a= 208

d = 8

l = 848

tn = a+ (n-1)d

848 = 208 +(n-1) 8

848 = 208 + 8n - 8

848 = 200 + 8n 

848 - 200 = 8n 

648 = 8n

n = 648/8

n = 81
sn = 46575

Thus, sum of all the multiples lying between 201 and 950 are 46575.

hope it help u

Answer 2

listen my friend this type of this type of question first find which is the first multiple of a number you have given that it is a multiple 8 between 201 to 9:50 ok so in this 208 is the first multiple of 8 and 9:44 is the last multiple of 8 and then the stuff