find the sum of all multiples of 8 lying between 201 and 950.
Answers
Answered by
43
a= 208
d = 8
l = 848
tn = a+ (n-1)d
848 = 208 +(n-1) 8
848 = 208 + 8n - 8
848 = 200 + 8n
848 - 200 = 8n
648 = 8n
n = 648/8
n = 81
sn = 46575
Thus, sum of all the multiples lying between 201 and 950 are 46575.
hope it help u
d = 8
l = 848
tn = a+ (n-1)d
848 = 208 +(n-1) 8
848 = 208 + 8n - 8
848 = 200 + 8n
848 - 200 = 8n
648 = 8n
n = 648/8
n = 81
sn = 46575
Thus, sum of all the multiples lying between 201 and 950 are 46575.
hope it help u
Vikhyath1:
mam in tis question 944 is last term not 848 .
Answered by
75
listen my friend this type of this type of question first find which is the first multiple of a number you have given that it is a multiple 8 between 201 to 9:50 ok so in this 208 is the first multiple of 8 and 9:44 is the last multiple of 8 and then the stuff
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