Find the sum of all multiples of 9 lying between 300 and 700.
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Answer:
306,315,324....
a=306
an= 693
693=306+(n-1)9
387 =(n-1)9
43=n-1
44=n
sn =n/2 [2a+(n-1)d]
= 693/2[6840]
= 693(3420)
=
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