Math, asked by kannankmala57, 1 month ago

find the sum of all natual number between 100 and 1000 which are divible by 11

Answers

Answered by bharath1056

2

Answer:

44550

Step-by-step explanation:

Tn=a+(n-1)d

999=111+(n-1)11

888/11=n-1

888/11+1=n

n=81

sn=n/2(2a+(n-1)d

sn=81/2(550×2)

sn=44550

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