Find the sum of all natura number between 250 and 1000 which are divisible by 9
Answers
Answered by
2
Answer:
52,542
Step-by-step explanation:
This would form an AP with common difference 9.
250, 251 are not divisible by 9, but 252 is divisible by 9.
First term = 252
Last term = 999
999 = 252 + (n-1)*9
n-1 = 83 => n = 84
S = n/2[a + l]
S = 84/2 [ 252 + 999 ]
=> 42 [1251]
=> 52,542
Similar questions