Question

find the sum of all natural no. between
100 and 300 which are divisible by 6

Answer 1

Arithmetic progression :-

100,104,108,……..3

a=100

d=4

l=300  

Now,

a+(n-1)d=300

[n-1] = 300 - a / d

[n-1] = (300–100)/4

[n-1] = 200/4

[n-1] = 50

n = 50+1

n = 51

Sum of A. P series will be

20200

Sum of all natural numbers between 100 and 300(divisible by 4) will be =20200–100–300

=19800.

Answer 2

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