Question

find the sum of all natural number between 100
1000 which are multiple of 6​

Answer 1

Step-by-step explanation:

102+108+---_--------_---------+996

a = 102

d = 6

an = 996

an = a +(n-1) d

996 = 102+(n-1)6

894 = 6n-6

900 = 6n

150 = n

s150= 150/2 (2×102+(150-1)6)

s150= 150/2 (204+149×6)

s150 = 150/2 (204+894)

s150 = 150/2(1098)

s150 = 150×549

s150 = 82350

Answer 2

Step-by-step explanation:

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