Question

find the sum of all natural number
between
100 and 500 which divisible by
8.
​

Answer 1

Answer:

15000

The sum of all natural number lying between 100 and 500 which is divisible by 8 = 15000.

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Step-by-step explanation:

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Answer 2

Answer:

15000 is the answer

Step-by-step explanation:

The numbers lying between 100 and 500 which are divisible by 8 are 104,112,120,128,136,...,496

a2 – a1 = 112 – 104 = 8

a3 – a2 = 120 – 112 = 8

∵ a3 – a2 = a2 – a1 = 8

Therefore, the series is in AP

Here, a = 120, d = 8 and an = 496

We know that,

an = a + (n – 1)d

⇒ 496 = 104 + (n – 1)8

⇒ 496 – 104 = (n – 1)8

⇒ 392 = (n – 1)8

⇒ 49 = (n – 1)

⇒ n = 50

Now, we have to find the sum of this AP

⇒ S50 = 25[208 + 49 × 8]

⇒ S50 = 25[600]

⇒ S50 = 15000

Hence, the sum of all numbers lying between 100 and 500 and divisible by 8 is 15000.

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