Question

find the sum of all natural number between 11 and 201 which are divisible by 5


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Answer 1

Answer:

Sum of all the no. between 11 and 201 Divisible by 5 = 4085

Step-by-step explanation:

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See The Attachment My Friend....

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Answer 2

Answer:

First number between 11 and 201 i.e

divisible by 5 = a = 5

last number divisible by 5 = an = 200

common difference d = 5

an = a +(n- 1)d

200 = 5 +(n -1)5

195 = 5 ( n- 1 )

39 = (n-1)

n= 40

Step-by-step explanation:

therefore 14 numbers between the 11 and 201 divisible by 5

11 and 201 divisible by 5

now = S40= 40/2 [2×5+39×5]

S40 = 20 [10+195]

S40= 20×205

S40= 4100

therefore sum of all number divisible by 5 is 4100