Find the sum of all natural number between 200 and 300 which are exactly divisible by 6
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1
Answer:
4032
Step-by-step explanation:
a= 204 = 300 n = ? d=6
= a+(n-1)d
300=204+(n-1)6
∴ n= 16
sₙ= n/2(a + aₙ)
= 16/2(204+300)
=8(504)
=4032
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