find the sum of all natural number between 250 and 100 which are divisival by 9
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answer: i guess the question is wrong it should be 1000 and not 100.
Sum of all Natural numbers between 250 and 1000 which are exactly divisible by 9 are 52542
Step-by-step explanation:
Natural numbers between 250 and 1000 which are exactly divisible by 9 are 252,261,...,999 is an A.P.
First term (a) = 252
last term (l) = 999
common difference (d)=9
l = 999
=> a+(n-1)d=999
=> 252+(n-1)d=999
Divide each term by 9, we get
=> 28 + n-1= 111
=> 27 + n = 111
=> n = 111 - 27
=> n = 84
Therefore,Sum of 84 terms in A.P =Sn
hope it helps you
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