Find the sum of all natural number between 250 and 1000 divisible by 8 Options are a) 48032 b) 58032 c) 7472 d) None of these
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Answer:
58032
Step-by-step explanation:
The 1st number after 250 divisible by 8 is 256 and 1000 is divisible by 8.
256=8×32. 1000=8×125
So there are 125-32+1=94 numbers between 250 and 1000 divisible by 8.
Their sum(n/2)(a+l)=94/2(256+1000)
47×1256=58032
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