find the sum of all natural number between 50 and 350 which are divisible by 5
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Step-by-step explanation:
this problem can be solved by Arithmetic Progression
A.P is 50, 55, 60-------350
here a = 50 , d = 5 and aₙ= 350
aₙ = a + (n-1)d
350 = 50 + (n-1)*5
350 = 50 + 5n - 5
350 = 45 + 5n
=> 5n = 350-45
=> 5n = 305
=> n = 61
now sum of 61 terms is
=> S₆₁ = 61/2 [ 2*50 + 60*5]
=> 61/2 [ 100 + 300 ]
=> 61/2 [400]
=> 200*61
=> 12200
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