Question

find the sum of all natural number form 1 to 10​

Answer 1

Sn = n/2[2a + (n-1)d]

Sn = 10/2[2 +9(1)]

Sn = 5(11)

Sn = 55

Hope it helps!

Mark my answer as brainliest!!

Answer 2

a=1,d=1,n=10

Sn=n/2(2a+(n-1)d)

S10=10/2(2×1+(10-1)×1

S10=5(2+9×1)

S10=5(11)

S10=55