find the sum of all natural number form 1 to 200
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Answer:
20100
Step-by-step explanation:
[n(n+1)]/2 is the formula to be used here.
Just put 200 in the place of n.
[200(200+1)]÷2
200 x 201 ÷ 2
40200 ÷ 2
= 20100
I really hope this helps you, fellow...
Bye :)
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