Question

find the sum of all natural number from 1 to 200 1.which is divisible by 5
2.which is divisible by 3​

Answer 1

I am solving
stop for while

Answer 2

Answer:

Step-by-step explanation:

Ap formed = 5,10,15.........200

A= 5 , d = 10-5=5

An=200

An=a + (n-1) d

200=5+(n-1)5

195=(n-1)5

195/5 = n-1

39+1 = n

N = 40

Sn = n/2 (a+an)

= 40/2(5+200)

= 20×205 = 4100

2. 3,6,.......198

An= a+(n-1)d

198=3+(n-1)3

195/3 = n-1

65+1=n

N=66

Sn = 66/2(3+198)

=33×201=6633