Find the sum of all natural number from 1 to 200 and which is divisible by 3
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Step-by-step explanation:
AP of no. divisible by 3 from 1 to 200-3,6,9,..... ,198
a=3 an or l=198 d=3
an=a+(n-1)d
198=3+(n-1)3
198-3=3(n-1)
195/3=n-1
n-1=65
n=65+1=66
Sn=n/2(a+l)
66/2(3+198)
33×201=6633
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Hope this helps.......
The answer is 59697
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