Question

Find the sum of all natural number from 1 to 200 and which is divisible by 3

Answer 1

Answer:

Step-by-step explanation:

AP of no. divisible by 3 from 1 to 200-3,6,9,..... ,198

a=3 an or l=198 d=3

an=a+(n-1)d

198=3+(n-1)3

198-3=3(n-1)

195/3=n-1

n-1=65

n=65+1=66

Sn=n/2(a+l)

66/2(3+198)

33×201=6633

Answer 2

Hope this helps.......

The answer is 59697