Question

Find the sum of all natural number lying between 100 and 500 , which are divisible by 8.

Answer 1

Hii friend,

All natural number between 100 and 500 which are divisible by 8 , are

104 , 112, 120 , 128 ,........... , 496

AP = 104,112,120,128.......,496

Here,

a = 104

D = (112-104) = 8

An = 496

An = a+(n-1) × d

496 = 104+(n-1) × 8

(n-1) × 8 = 496-104

(n-1) × 8 = 392

(n-1) = 392/8

n-1 = 49

n = 49+1

n = 50

Required sum = N/2 (a+An)

= 50/2 × (104+496)

= (25×600) = 15000

Hence,

The sum of all natural number lying between 100 and 500 which is divisible by 8 = 15000.


HOPE IT WILL HELP YOU..,.... :-)

Answer 2

pl mark it as brainliest