find the sum of all natural number which is less than 200 and divisible by 5 (by arithmetic progressions)
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nothing but pls make me brsinlidt
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Step-by-step explanation:
hlo mate....
Your solution is here:-
A.P =Natural no. divisible by 5 less than 200.
= 5,10,15.......195.
From the A.p we can now find out.
d (common difference)= 10-5=5
a=5 an^th term=195.
Sum of n no. =n/2(a+an ^th term.)
but first of all we have to calculate n .
From the formula=an^th term =a+(n-1)d
195 =5 +(n-1) 5
190/5 = n-1
38 =n-1
n=39...
Now we can calculate sum....by simply putting values in it..
sn=39/2 (5+195)=39/2(200) =3900
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Thanku
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