Question

find the sum of all natural number which is less than 200 and divisible by 5 (by arithmetic progressions)
​

Answer 1

Answer:

nothing but pls make me brsinlidt

Answer 2

Step-by-step explanation:

hlo mate....

Your solution is here:-

A.P =Natural no. divisible by 5 less than 200.

= 5,10,15.......195.

From the A.p we can now find out.

d (common difference)= 10-5=5

a=5 an^th term=195.

Sum of n no. =n/2(a+an ^th term.)

but first of all we have to calculate n .

From the formula=an^th term =a+(n-1)d

195 =5 +(n-1) 5

190/5 = n-1

38 =n-1

n=39...

Now we can calculate sum....by simply putting values in it..

sn=39/2 (5+195)=39/2(200) =3900

Follow me 4 more queries...

Thanku