Question

find the sum of all natural numbers between 1 and 100 which are multiples of 3​

Answer 1

Answer:

Answer:

The sum of all natural numbers between 1 and 100, which are divisible by 3 are 1683.

Step-by-step explanation:

Given :  

Natural numbers between 1 and 100 which are divisible by 3 are 3, 6, 9, 12, ……….99

Here,  first term , a = 3, last term, l = 99, common Difference, d = 6 - 3 = 3

By using the formula ,an = a + (n - 1)d

99 = 3 + (n - 1)3

99 = 3 + 3n - 3

99 = 3n

n = 99/3

n = 33

By using the formula ,Sum of nth terms , Sn = n/2 [a + l]

S33 = 33/2 [3 + 99]

S33 = 33/2 × 102

S33 = 33 (51)  

S33 = 1683

Hence, the sum of all natural numbers between 1 and 100, which are divisible by 3 are 1683.

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Step-by-step explanation:

Answer 2

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