find the sum of all natural numbers between 1 and 100 which is divisible by 6
Bittu1211:
786
no answer is wrong
answer is 16
817
sry
816
what is correct answer
100/6, remainder = 4
So an= 96 , 96 = 6 +( n -1)6, n=16
An= n/2*(2a +( n-1) d)
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