Question

Find the sum of all natural numbers between 1 and 145 which are divisible by 4​

Answer 1

Answer : 36 is the answer !!

Step-by-step explanation :

Just divide 144 , which is a last number divisible between 1 & 145 , by 4 .

Or

Find the answer by an=a+(n-1)d

HOPE YOU UNDERSTAND IT !!!!!

Answer 2

first no. which is divisible by four is 4 itself

so a=4

145 ÷ 4

q=36

remainder =1

therefore 145-1

=144

therefore an=144

d=4

because every no. after four we add four will be divisible by four as it is a multiple of 4

we need to find n first

an = a+ ( n-1)d

144 = 4+(n-1)4

144-4=(n-1)4

140/4=n-1

35 + 1=n

36 =n

sum of n= n/2×(a+an)

=36/2(4+144)

=18×148

=2664

hope it helps you

mark as braiinliest if useful

#answerwithquality

#BAL