Question

find the sum of all natural numbers between 1 and 145 which are divisible by 4​

Answer 1

refer to the attachment below

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Answer 2

Answer:

Step-by-step explanation:

Natural numbers between 1 to 145 divisible by 4 are

4,8,12.........144

The given sequence is an AP

Where a = 4

D=4

tn = 144

Since we know that ,

tn = a+(n-1) d

144=4+(n-1)4

144= 4+4n-4

144 =4n

N=144÷4

n=36

Since we know that

Sn=n÷2 [ t1 + tn ]

S 36 = 36÷2 [ 4 + 144 ]

S36 = 18 × 148

S36 = 2664

Sum of all natural numbers between 1 to 145 divisible by 4 is 2664