Question

) Find the sum of all natural numbers between 10 and 200 which are divisible by 4

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Answer 1

Answer:

a=12,l=200,n=?

l=a+(n-1)d

200=12+(n-1)4

200-12=(n-1)4

188/4=n-1

47=n-1

n=48

Sn=n/2(a+l)

=48/2(12+200)

=48/2(212)

=24(212)

=4688