Question

find the sum of all natural numbers between 100 and 1000 which are divisible by 11​

Answer 1

Answer:

hshdgrhdjjsdhhdjdhdh

Step-by-step explanation:

bdhdbdjjdjdjfjfkkdjfjjcjdkdjhddhjjd

Answer 2

Answer:

98450

Step-by-step explanation:

Natural numbers b/w 100 and 1000 which are multiples of 5 are :

105,110,115,.........,990,995.

a=105, d=5

a

n

=995

a+(n−1)d=995

105+(n−1)5=995

(n−1)5=890

n−1=178

n=179

Hence,

S

n

=

2

n

[2a+(n−1)d]

S

179

=

2

179

[210+890]

S

179

=

2

179

×1100=98450