find the sum of all natural numbers between 100 and 1000 which are divisible by 2 as well as 5
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S=110+120+..................................+990
here the sequence is in AP
now ,a=110,d=10,a(n)=990
we know that:
a(n)=a+(n-1)d
990=110+(n-1)×10
(n-1)=(990-110)/10
n-1=880/10=88
n=88-1=87
S=n/2{2a+(n-1)d}
S=n/2{a+a(n)}
S=87/2{110+990}=87/2{110}=87×550=47850
please mark me brainliest
here the sequence is in AP
now ,a=110,d=10,a(n)=990
we know that:
a(n)=a+(n-1)d
990=110+(n-1)×10
(n-1)=(990-110)/10
n-1=880/10=88
n=88-1=87
S=n/2{2a+(n-1)d}
S=n/2{a+a(n)}
S=87/2{110+990}=87/2{110}=87×550=47850
please mark me brainliest
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