Find the sum of all natural numbers between 100 and 300 [(a) including both of these, and (b) excluding
both of these] :
(1) Which are exactly divisble by 4.
(ii) Which are exactly divisible by 5.
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Answer:
(i)a=104 d=4 an=208
an=a+(n-1)d
208=104+(n-1)4
104÷4=n-1
26+1=n
n=27
sn=n/2(a+an)
27/2(104+208)
27/2×312
27×156
4212
Step-by-step explanation:
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