Question

find the sum of all natural numbers between 100 and 300 (a) including both of these, and (b) excluding both of these​

Answer 1

Answer:

sorry I 'am not slove this

Step-by-step explanation:

sorry sorry

Answer 2

Answer:

The numbers into consideration are from 101 to 299 as stated by the question.

So, the first number in the range that is divisible by five is 105, and the last one is 295.

Notice that it is an arithmetic progression, The sum is some thing like this :

S = 105 + 110 + 115 +…..+ 290 + 295

Notice that the common difference is 5.

The number of terms in this series is equal to the index number of the last term in our series.

l=a+(n−1)d

295=105+5(n−1)

Or, (n−1)=(295−105)5

Or, (n−1)=1905

Or, n=38+1

Or, n=39

So, the sum of the series will be :

S=n[a+l]2

S=39[105+295]2

S=39.4002

S=39.200

S=7800

Thus, the answer is 7400.

With regards.