Find the sum of all natural numbers between 100 and 300 [(a) including both of these and (b) excluding both of these]:
(i) which are exactly divisble by 4, (ii) which are exactly divisible by 5,
(iii) which are exactly divisible by 4 and 5, (iv) which are exactly divisible by 4 or 5,
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(i)a=104 d=4 an=208
an=a+(n-1)d
208=104+(n-1)4
104÷4=n-1
26+1=n
n=27
sn=n/2(a+an)
27/2(104+208)
27/2×312
27×156
4212
kumar3193129:
worng answer
Answered by
2
Answer:
Step-by-step explanation:
Use the formula tn=a +(n-1)d and when u will find the value of n then use the formula of
Sn=n/2[2a+ (n-1)d]
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