Question

Find the sum of all natural numbers between 101 and 304 which are divisible by 3 or 5

Answer 1

Answer:

19035

Step-by-step explanation:

303 = 102 + 3n -3 , n = 204/3 = 68

Divided by 3 = S3 =  68/2(102+303) = 13770

300 = 105 + 5n -5 , n = 200/5 = 40

Divided by 5 = S5 =  40/2(105+300) = 8100

300 = 105 + 15n -15 , n = 210/15 = 14

Divided by 15 = S15 =  14/2(105+300) = 2835

sum required = S3 + S5 - S15 = 13770 + 8100  - 2835 = 19035

Answer 2

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