Question

Find the sum of all natural numbers between 200 and 1000 which are divisible by 8
Class 10​

Answer 1

Step-by-step explanation:

200÷8= 25

1000÷8=125

We know in arithmetic progress

Sum of terms=n/2(a+l)

Where 'n'= total numbers (here 125-35=100)

'a'= first terms

'l'= last term

Sum =100÷2(25+125)

=50*150

=7500 ans