Find the sum of all natural numbers
between 200 and 1000 which are multiples
of 10.
Answers
Answered by
10
GIVEN:
Numbers: 200, 210, ...... , 1000
- a = 200
- d = 10
- an = 1000
TO FIND:
- Find the sum of all natural numbers between 200 and 1000 which are multiples of 10.
SOLUTION:
To find how much numbers are present between 200 and 1000 which are multiple of 10.
an = a + ( n - 1 ) d
1000 = 200 + ( n - 1 ) 10
800/10 = n - 1
n = 81
Total numbers present is 81.
Equation of Sum, Sn = n/2 [ a + an ]
=> Sn = 81/2 [ 200 + 1000 ]
=> Sn = 81/2 x 1200
=> Sn = 81 x 600
=> Sn = 48600
Therefore, the sum of all natural numbers between 200 and 1000 which are multiples of 10 is 48600.
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