Question

find the sum of all natural numbers between 200 and 300 which is exactly divisible by 6

Answer 1

Starting no. Which is divisible by 6= 204
Then a=204
n=no. Of total terms =16
d=6
l=300
S=(a+l)n/2
=(204+300)8=8*504=4032

Answer 2

Answer:

The sum of all natural numbers between 200 and 300 which is divisible by 6 is 4032.

Solution:

Given, the last term I = 300

Numbers divisible by 6, n = 16 [i.e. 204, 210, 216, 222, 228, 234, 240, 246, 252, 258, 264, 270, 276, 282, 288, 294, 300]  

First number divisible by 6, a= 204

The formula for sum in Arithmetic Progression is,

$S=\frac{n}{2}\{a+I\}=\frac{16}{2}\{204+300\}$

$S=8 \times 504=4032$

Therefore, the sum is 4032.