find the sum of all natural numbers between 200 and 300 which are divisible by 4
Answers
Answered by
5
pl mark it as brainliest
Attachments:
Answered by
0
Step-by-step explanation:
204,208,212,.....296
a=204,an=296&d=4
an=a+(n-1) ×d
296=204+(n-1)×4
92/4=n-1
n=23+1
=24
an=n/2(a+l)
=24/2 ×[204+296]
=24×250
=6000
Similar questions