find the sum of all natural numbers between 200and 300 which are exactly divisible by 6
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AP: 204,210,216...294
a1=204
a2=210
d=a2-a1= 210-204=6
an=a+(n-1)d
294=204+(n-1)6
294-204=(n-1)6
90/6=n-1
15=n-1
n=16
Sn=n/2 (a+an)
=16/2 (204+294)
=8×498=3984 Ans.
a1=204
a2=210
d=a2-a1= 210-204=6
an=a+(n-1)d
294=204+(n-1)6
294-204=(n-1)6
90/6=n-1
15=n-1
n=16
Sn=n/2 (a+an)
=16/2 (204+294)
=8×498=3984 Ans.
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