Question

Find the sum of all natural numbers
between 250 and 1000 which is exactly
divisible by 3​

Answer 1

Answer:

Step-by-step explanation:

The first number after 250 divisible by 3 is 252. and the number just before 1000 divisible by 3 is 999. So there are 333–84+1 = 250 numbers between 250 and 1000 divisible by 3. Their sum = (n/2)(a+l) = (250/2)(252+999) = 156375.

Answer 2

156375 is answer of this question

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