Find the sum of all natural numbers between 250 and
1000 which are exactly divisible by 4.
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Answer:
Clearly the number between 250 & 1000 which are 252,255,258............999
this is a A.P with first term a = 252 common different =3 and last term =999
let there be n terms in this A.P
then An=999
a+(n-1) d =999
252+(n-1)*3=999
n=250
required sum =Sn=n/2 ( a+ l )
250/2 ( 252 + 999) =156375
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