Find the sum of all natural numbers between 307 and 500 which are divisible bye 6??? Plssss answer this question its very important!!!!:-§
Answers
Answered by
6
The closest number greater than, 307 divisible by 6 is 312 and the closest number less than 500, divisible by 6 is 498. So, use AP. 312 is first term, 498 is last term and common difference is 6. So, a+(n-1)d=l. Solving, we get n to be 32. So there are 32 numbers divisible by six between 307 and 500.
domy:
Hmmm thank you :-)
You're welcome. Do mark as Brainliest :)
So sorry, I did not read the part where you told to find the sum.. But as the other person has answered that, I'll not edit now.
Its ok you told me this much I get to know that how to solve this problem!! No problem you tell me this much I thank to you!!!!
Answered by
12
AP:312,318,...........,498.
a=312
d=6
n=?
an=l=498
an=a+(n-1)*d
498=312+(n-1)*6
186=6n-6
6n=192
n=32
Therefore, 32 numbers are divisible by 6 between 307&500.
Sn=n/2*(a+l)
=32/2*(312+498)
=16*810
=12960.
a=312
d=6
n=?
an=l=498
an=a+(n-1)*d
498=312+(n-1)*6
186=6n-6
6n=192
n=32
Therefore, 32 numbers are divisible by 6 between 307&500.
Sn=n/2*(a+l)
=32/2*(312+498)
=16*810
=12960.
Thank you so much :-D
You're Welcome :)
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