Question

find the sum of all natural numbers
betwen 50 to 250 which are divisible by 3.​

Answer 1

Answer:

AP-54,57............249

A=54

D=3

An=249

An=A+(N-1)D

249=54+(N-1)3

249-54/3=N-1

65=N-1

N=66

Sn=N/2(A+L)

Sn=66/2(54+249)

Sn=33×303

Sn=9999

HOPE THE ANSWER IS RIGHT