find the sum of all natural numbers
betwen 50 to 250 which are divisible by 3.
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Answer:
AP-54,57............249
A=54
D=3
An=249
An=A+(N-1)D
249=54+(N-1)3
249-54/3=N-1
65=N-1
N=66
Sn=N/2(A+L)
Sn=66/2(54+249)
Sn=33×303
Sn=9999
HOPE THE ANSWER IS RIGHT
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