Question

Find the sum of all natural numbers divisible by
5, from 150 to 200.​

Answer 1

Answer:

The sum is 1225

Solution :

The numbers from 150 to 200 divisible by 7 are 154,161 ,168,…., 196

Here, a=154,d=7 and tn=196

tn=a+(n−1)d …(Formula )

∴196=154+(n−1)×7 …(Substituting the values )

∴196−154=(n−1)×7

∴427=n−1 ∴n−1=6 ∴n=7

Now, we find the sum of 7 numbers.

Sn=n2[t1+tn] ...(Formula )

=72[154+196)

=72×350

=7×175

=1225

Answer 2

here's your answer

hope it helps you