find the sum of all natural numbers from 1 to 100
Answers
Answered by
5
a = 1
d = 1
L = 100
=> a + (n-1)d = 100
=> 1 + (n-1) (1) = 100
=> 1 + n - 1 = 100
=> n = 100
Now,
Sn = 100/2 ( 1 + 100)
= 50 × 101
= 5050
d = 1
L = 100
=> a + (n-1)d = 100
=> 1 + (n-1) (1) = 100
=> 1 + n - 1 = 100
=> n = 100
Now,
Sn = 100/2 ( 1 + 100)
= 50 × 101
= 5050
Answered by
3
sum of all natural number from 1 to 100 is
100/2×( 2×1 + (100 -1) 1 )
=50× (2+99)
=50 × 101
=5050.
100/2×( 2×1 + (100 -1) 1 )
=50× (2+99)
=50 × 101
=5050.
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