Find the sum of all natural numbers from 1 to 100 which are not multiples of 4.
Answers
Answered by
5
Answer:
3750
Step-by-step explanation:
For the sum of all numbers from 1 to 100:
Using the properties of AP: In this AP, a = 1, d = 1, l = 100
So there are 100 terms, hence sum of all of these numbers is:
⇒ (n/2) [ a + l ]
⇒ (100/2) ( 1 + 100 ) ⇒ 50( 101 )
⇒ 5050
For the sum of all number from 1 to 100( which have 4 as factor ):
In this AP, a = 4, d = 4, l = 100, let there n terms
⇒ nth term = a + ( n - 1 )d { formula}
⇒ 100 = 4 + ( n - 1 )4
⇒ 96/4 = n - 1
⇒ 24 = n - 1 ⇒ 25 = n
Hence,
⇒ their sum = (25/2)( 4 + 100 )
= (25/2)( 104 )
= 1300
Hence,
⇒ sum of numbers which are not multiples of 4:
⇒ 5050 - 1300
⇒ 3750
Answered by
8
Answer:
3750 is the correct answer please make as braniist
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