Question

Find the sum of all natural numbers from 1 to 120 which are divisible by 3​

Answer 1

Answer:

2,460

Step-by-step explanation:

Natural numbers from 1 to 120 which are divisible by 3 =

3+6+9+12+15+18+21+24+27+30+33+36+39+42+45+48+51+54+57+60+63+66+ 69+72+75+78+81+84+87+90+93+96+99+102+105+108+111+114+117+120 = 2,460

Answer 2

Answer:

2460

Step-by-step explanation:

First number divisible by 3 is 3

Last number divisible by 3 is 120

Therefore the total number of terms

an=a+(n-1)d

120=3+( n-1)3

n-1= 117/3

n-1=39

n=40

Now sum of 40 terms

=n(a+l)/2

=40*123/2

=2460