Question

Find the sum of all natural numbers from 200 and 300 which are exactly divisible by 6.
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Answer 1

Answer:

Step-by-step explanation:

204+210+...+300

Total number=n(let)

Now, 300=204+(n-1)×6

n=17

Sum=17/2×(204+300)=4284

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Answer 2

Answer:

Step-by-step explanation:

Given, the last term I = 300

Numbers divisible by 6, n = 16 [i.e. 204, 210, 216, 222, 228, 234, 240, 246, 252, 258, 264, 270, 276, 282, 288, 294, 300]  

First number divisible by 6, a= 204

The formula for sum in Arithmetic Progression is,

S=\frac{n}{2}\{a+I\}=\frac{16}{2}\{204+300\}

S=8 \times 504=4032

Therefore, the sum is 4032.

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