Question

find the sum of all natural numbers from 200 and 300 which are exactly divisible by 6


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Answer 1

Answer:

4284

Step-by-step explanation:

a ( First no: ) = 204

b ( Last no: ) = 300

d ( Common difference ) = 6

a + d ( n - 1 ) = b

204 + 6 ( n - 1 ) = 300

6 ( n - 1 ) = 96

n - 1 = 16

∴ n = 17

S = $\frac{n ( a + b )}{2}$

⇒

∴ S = $\frac{17 ( 204 + 300 )}{2}$ = $\frac{17 * 504}{2}$ = $\frac{17*252}{1}$ = 4284

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