Question

find the sum of all natural numbers from 50 to 250 which are xctly divisible by 4

arithmetic progression

Answer 1

Step-by-step explanation:

50 to 250 divisible by 4

comman difference ( d ) = 4

first term ( a ) = 52

last tern (tn ) = 248

tn = a + ( n-1 )×d

248 = 52 + (n-1 )×4

248 = 52 + 4n - 4

248 = 48 + 4n

248-48÷4 = n

200÷4

50

n = 50

Now sum of all terms

Sn = n÷2 ( a + tn )

50÷2 (52 + 248 )

25 ( 300

25×300

7500

7500 is ur answer

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