Question

find the sum of all natural numbers less than 100 divisible by 4

Answer 1

the smallest natural numbr divisible by 4=4
the largest number inside 100 =96
thus a=4
d=8-4=4
n=?
an=96
an=a+(n-1)d
96=4+(n-1)4
96-4=4n-4
92+4=4n
96=4n
n=96/4
n=24
you can directly find n by directly multiplying 96/4
now,
sn=n/2(2a+(n-1)d)
or
sn=n/2(a+l)
 
so when we do it,we get
sn=24/2(4+96)
sn=1200
hope it helps!!
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Answer 2

hope this answer helped you
out is a verified answer